动态规划问题!
构造计算矩阵:
代码示例
默认是两个长度为5的子序列
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/*
* @Author: MetaNetworks
* @Date: 2019-10-31 11:34:11
* @LastEditors: MetaNetworks
* @LastEditTime: 2019-10-31 15:24:25
* @Description: MetaNetworks' Code
*/
#include <iostream>
#include <stdlib.h>
#include <stack>
#define NUM 5
#define NOTSET -1
using namespace std;
char str_a[] = " CBDCA";
char str_b[] = " BDCAB";
// 字符串在 0-4,5是反斜杠0,也是无效字符
int mat[NUM+1][NUM+1];
int cal(int x,int y){
if (mat[x][y] == NOTSET)
{
if (str_a[x-1]==str_b[y-1])
{
mat[x][y] = cal(x-1,y-1) + 1;
}
else{
mat[x][y] = max(cal(x-1,y),cal(x,y-1));
}
}
return mat[x][y];
}
stack<int> s;
void getIndex(int x,int y){
while(mat[x][y]!=0){
if(str_a[x]==str_b[y]){
// 相等则 往stack传入x
s.push(x);
getIndex(x-1,y-1);
}
else{
// 不等,则由最大的继承
if(mat[x-1][y]>mat[x][y-1]){
getIndex(x-1,y);
}
else{
getIndex(x,y-1);
}
}
return;
}
// 输出
while (!s.empty())
{
int index = s.top();
cout<<str_a[index];
s.pop();
}
}
int main(){
// reset to 0
for (int j = 0; j <= NUM; j++)
{
for(int k=0;k <= NUM;k++){
mat[j][k] = NOTSET;
}
}
// 0
for (int i = 0; i <= NUM; i++)
{
mat[0][i] = 0;
mat[i][0] = 0;
}
cout<<cal(NUM,NUM)<<endl;
for (int j = 0; j <= NUM; j++)
{
for(int k=0;k<=NUM;k++){
cout<<mat[j][k]<<" ";
}
cout<<endl;
}
getIndex(NUM,NUM);
}